Example) By using the Mollier diagram of R-22, find the compression ratio, refrigeratiny effect, work of compres-
sion, calorie of condensation, circulation amount of refrigerant, coefficient of performance, and refriger-
ating effect per 1KW.
Condensation pressure : Pd = 18.1kg/cm
2
abs
Evaporation pressure : Ps = 6.5kg/cm
2
abs
Compression ratio : Pr = Pc/Pe = 18.1/6.5 = 2.78
Enthalpy : iA = 148.5kcal/kg
iB = 158.5kcal/kg
iC = 110kcal/kg
iD = 110kcal/kg
iC' = iD'= 112kcal/kg
iE = 148kcal/kg
Accordingly, Refrigerating effect : q1 = iA - iD = 148.5 - 110 = 38.5 [kcal/kg]
Work of compression : A1 = iB - iA = 158.5 - 148.5 = 10 [kcal/kg]
Calorie of condensation : q2 = iB - iC = 158.5 - 110 = 48.5 [kcal/kg]
Circulation amount of refrigerant : G=Q/q1 = 3320/38.5 = 86.2 [kg/h.RT] (per 1 Refrigerating Ton)
COP : q1/A1 = 38.5/10 = 3.85
Refrigerating effect per 1KW : k = 860 x 3.85 = 3311 [kcal/h. KW]