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11.2. Capacity And Power Consumption
11.2.1. Cooling performance
Calculation of actual cooling capacity and power consumption:
Example: CS-F24DB4E5 / CU-YL24HBE5
• Calculation of the actual cooling capacity and power consumption for the following cooling conditions;
Indoor temperature of 27/19°C and outdoor temperature of 40°C (Standard condition).
Calculation method
1. Find the cooling capacity ratio and the power consumption ratio from the cooling capacity graph and power consumption graph for model
CS-F24DB4E5 / CU-YL24HBE5.
• The cooling capacity ratio indicate at the intersection between an outdoor unit air inlet temperature of 40°C on the horizontal axis and an
indoor unit air inlet temperature on 27/19°C is 0.95.
• The cooling power consumption ratio from the same intersection on the power consumption graph is 1.03.
2. Thus,
• Actual cooling capacity = cooling capacity ratio x rated cooling capacity = 0.95 x 6.3 = 5.985 (kw).
• Actual cooling power consumption = cooling power consumption x rated power consumption = 1.03 x 2.2 = 2.266 (kw).
Model name Max cooling capacity
Max capacity (kw) Max power consumption (kw)
CS-F14DB4E5 × 2 / CU-YL28HBE5 7.7 2.6
CS-F18DB4E5 × 2 / CU-YL34HBE5 11 3.95
CS-F24DB4E5 × 2 / CU-YL43HBE5 13 4.45
CS-F24DB4E5 / CU-YL24HBE5 6.3 2.2
CS-F28DB4E5 / CU-YL28HBE5 7.7 2.6
CS-F34DB4E5 / CU-YL34HBE5 11 3.95
CS-F43DB4E5 / CU-YL43HBE5 13 4.45
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