Siemens SIMOTICS S-1FL6 User Manual

Appendix
A.2 Motor selection
SINAMICS V90, SIMOTICS S-1FL6
Operating Instructions, 04/2019, A5E36037884-007
425
A.2.3
Selection examples
This section uses a ball screw mechanism as an example to illustrate the motor selection
procedure.
Exemplary data
The following table lists the data related to the ball screw mechanism and operation pattern.
Mechanism
Operation pattern
Workpiece weight (W)
40 kg
Acceleration time (t
a
)
0.15 s
Ball screw length (B
l
) 2 m Constant motion time (t
u
) 0.7 s
Ball screw diameter (B
d
)
0.04 m
Deceleration time (t
d
)
0.15 s
Ball screw pitch (B
p
) 0.04 m Cycle time (t
c
) 2 s
Mechanical efficiency (B
ŋ
)
0.9
Travel distance (L)
0.5 m
Coupler inertia (J
c
) 20 x 10
-6
kg·m
2
(refer to
the supplier's product
catalog)
-
1.
Ball screw weight
B
w
= ρ x π x (Bd/2)
2
x B
l
= 19.85 kg
2.
Load inertia
J
l
= J
c
+ J
b
= J
c
+ 1/8 x B
w
x B
d
2
+ W x B
p
2
/ 4π
2
= 5.61 x 10
-3
kg·m
2
3.
Preselection
If a 1000 W motor is selected, J
m
(motor inertia) = 1.57 x 10
-3
kg·m
2
Therefore, J
l
/ J
m
(inertia ratio) = 3.57 < 5 times
4.
Maximum rotational speed
V
max
(maximum travelling speed) = 2L / (t
a
+ 2t
u
+ t
d
) = 5.89 m/s
N
max
(maximum rotational speed) = 60 x V
max
/ B
p
= 882 rpm < 2000 rpm (rated speed)
5.
Effective torque
T
m
(moving torque) = (μgW + F) x B
p
/ 2πB
η
= 0.069 Nm
T
a
(acceleration torque) = [(J
l
+ J
m
) x 2 πN / T
a
] + T
m
= 4.49 Nm
T
d
(deceleration torque) = [(J
l
+ J
m
) x 2 πN / T
d
] - T
m
= 4.35 Nm
Therefore, T
rms
(effective torque) =√(T
a
2
x t
a
+ T
m
2
x t
b
+ T
d
2
x t
d
) / t
c
= 1.71 Nm < 4.78 Nm
(rated torque)
6.
Final selection
According to the above calculated speed, torque, and inertia ratio, you are recommended
to select 1000 W motors, i.e. 1FL6062.

Siemens SIMOTICS S-1FL6 Specifications

General

Brand	Siemens
Model	SIMOTICS S-1FL6
Category	Servo Drives
Language	English