Xerox 550 User Manual

Bits 0-24 of register 1 are cleared and the remaining count
is loaded into bits 25-31. If the initial contents of bit 0
is equal to 1, then no bits are shifted by the instruction.
In this case the original count in the instruction is stored
in
register 1.
Searching shift causing a change in bit position 0 causes
CC2 to be set to 1. If bit posi tion 0 is not changed during
a
searching shift, CC2 is cleared. CC4 is set to 1 if the
shift is terminated with a 1 in bit position O.
Affected: (R), (Rl), CC2, CC4
Searching Shift, Double Register
The
searching shift is circular in either direction. If the
shift count, C, is positive, the contents of registers Rand
Ru1 are shifted left C bit positions or until a 1 appears in
bit posi tion 0 of register R. If C is negative, the contents
are shifted right lei posi tions or unti I a 1 appears in bit
posi tion O. When the shift is terminated, the remaining
count is stored in register 1, which is dedicated to the
searching shift instruction. Bits 0-24 of register 1 are
cleared and the remaining count is loaded into bits 25-31.
Searching shift causing a change in bit position 0 causes
CC2 to be set to 1. If bit position 0 is not changed during
a
searching shift, CC2 is cleared. CC4 is set to 1 if the
shift is
terminated with a 1 in bit position O.
Affected: (R), (Rul), (Rl), CC2, CC4
FLOATING-POINT SHIFT
Floating-point numbers are defined in the "Floating-
Point Arithmetic Instructions" section. The format for the
floating-point shift instruction is:
SF SHIFT FLOATING
0/lord
index alignment)
If direct addressing and no indexing is called for in the in-
struction SHIFT FLOATING, bit position 23 of the reference
address field determines the type {long or short format} of
shift, and bit positions 25-31 determine the direction and
amount of the shift.
If
indirect addressing and no indexing is called for in the
instruction, bit positions 15-31 of the instruction are used
to
access the indirect word and then bit positions 23 and
25-31 of the indirect word determine the type, direction,
and amount of the shift.
If
direct addressing and indexing are called for in the
instruction, bit 23 of the reference address (not affected
by subsequent indexing) determines the type of shift.
Bits 25-31
of the reference address plus bits 25-31 of the
specified indexed register determine the direction and
amount of the shift.
If indirect addressing and indexing are called for in the in-
struction, bits 15-31 of the reference address are used to
access the indirect word. Bit 23 of the indirect word (not
affected by subsequent indexing) determines the type of
shift. Bits 25-31 of the indirect address plus bits 25-31 of
the specified index register determine the direction and
amount of the shift.
The shift count, C, in bit positions 25-31 of the effective
virtual address determines the amount and direction of
the shift. The shift count is treated as a 7-bit signed
binary integer, with the high-order bit (bit position 25) as
the sign (negative integers are represented in twols com-
plement form).
The
absolute value of the shift count determines the number
of hexadecimal digit positions the floating-point number is
to be shifted. If the shift count is positive, the floating-
point number is shifted left; if the count is negative, the
number is shifted right.
SHIFT FLOATING loads the floating-point number from the
register(s) specified by the R field of the instruction into a
set of internal registers. If the number is negative, it
is twols complemented. A record of the original sign is
retained. The floating-point number is then separated into
a characteristic and a fraction, and CCl and CC2 are both
reset to OIS.
A positive shift count produces the following left shift
operations:
1. If the fraction is normalized (i. e., is less than 1 and
is equal to or greater than 1/16), or the fraction is
a" OIS, CCl is set to 1.
2. If the fraction field is all OIS, the entire floating-point
number is set to all OIS ("true" zero), regardless of the
sign and the characteristic of the original number.
3. If
the fraction is not normalized, the fraction field is
shifted 1 hexadecimal digit position (4 bit positions) to
the left and the characteristic field is decremented
by 1. Vacated digit positions at the right of the frac-
tion are fi lIed with hexadecimal OIS.
If the characteristi c fie Id underflows (i. e., is all lis
as the result of being decremented), CC2 is set to l.
However, if the characteristic field does not under-
flow, the sh ift process (sh ift fracti on, and decre-
ment characteristic) continues until the fraction is
normalized, unti I the characteristic field underflows,
or unti I the fraction is shi fted left C hexadeci ma I
digit positions, whichever occurs first. (Any two,
or all three, of the terminating conditions can occur
simultaneously. )
Shift Instructions 71

Xerox 550 Specifications

General

Brand	Xerox
Model	550
Category	Printer
Language	English